-16x^2+48x+288=0

Solution for -16x^2+48x+288=0 equation:

-16x^2+48x+288=0

a = -16; b = 48; c = +288;
Δ = b2-4ac
Δ = 482-4·(-16)·288
Δ = 20736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{20736}=144$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-144}{2*-16}=\frac{-192}{-32}
=+6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+144}{2*-16}=\frac{96}{-32}
=-3
$